The 1948 United States presidential election in Montana took place on November 2, 1948. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.Montana voted for the Democratic nominee, President Harry Truman, over the Republican nominee, New York Governor Thomas E. Dewey. Truman won Montana by a substantial margin of 9.94 percent.

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dbo:abstract
  • The 1948 United States presidential election in Montana took place on November 2, 1948. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.Montana voted for the Democratic nominee, President Harry Truman, over the Republican nominee, New York Governor Thomas E. Dewey. Truman won Montana by a substantial margin of 9.94 percent. As of the 2016 presidential election, this is the last election in which Carter County and Prairie County voted for a Democratic Presidential candidate. (en)
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  • 2018-05-08 02:35:21Z (xsd:date)
  • 2019-06-20 05:16:10Z (xsd:date)
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  • Democratic Party (en)
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  • Democratic Party (en)
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  • Montana (en)
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  • 1948-11-02 (xsd:date)
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  • United States presidential election in Montana, 1948 (en)
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  • County results (en)
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  • MT1948president.png (en)
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  • United States presidential election in Montana, 113452 (en)
  • United States presidential election in Montana, 1952 (en)
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  • United States presidential election in Montana, 1944 (en)
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  • The 1948 United States presidential election in Montana took place on November 2, 1948. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.Montana voted for the Democratic nominee, President Harry Truman, over the Republican nominee, New York Governor Thomas E. Dewey. Truman won Montana by a substantial margin of 9.94 percent. (en)
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  • United States presidential election in Montana, 1948 (en)
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