The 1896 United States presidential election in Montana took place on November 3, 1896. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.Montana overwhelmingly voted for the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan over the Republican nominee, former governor of Ohio William McKinley.

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  • The 1896 United States presidential election in Montana took place on November 3, 1896. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.Montana overwhelmingly voted for the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan over the Republican nominee, former governor of Ohio William McKinley. Bryan won Montana by a landslide margin of 60.22 percentage points.Bryan's support for many Populist goals resulted in him being nominated by both the Democratic Party and the People's Party (Populists), though with different running mates. One electoral vote from Montana was cast for the Populist Bryan-Watson ticket with Thomas E. Watson as Vice-President and two votes were cast for the Bryan-Sewall ticket. (en)
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  • Republican Party (en)
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  • Democratic Party (en)
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  • Montana (en)
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  • 1896-11-03 (xsd:date)
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  • United States presidential election in Montana, 1896 (en)
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  • County results (en)
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  • United States presidential election in Montana, 1900 (en)
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  • United States presidential election in Montana, 1892 (en)
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  • The 1896 United States presidential election in Montana took place on November 3, 1896. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.Montana overwhelmingly voted for the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan over the Republican nominee, former governor of Ohio William McKinley. (en)
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  • United States presidential election in Montana, 1896 (en)
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